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4s^2-24s-50=0
a = 4; b = -24; c = -50;
Δ = b2-4ac
Δ = -242-4·4·(-50)
Δ = 1376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1376}=\sqrt{16*86}=\sqrt{16}*\sqrt{86}=4\sqrt{86}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{86}}{2*4}=\frac{24-4\sqrt{86}}{8} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{86}}{2*4}=\frac{24+4\sqrt{86}}{8} $
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